A rhombus has sides of length 10cm, and the angle between two adjacent sides is 76°. Find the length of the longer diagonal of the rhombus
Answers
Answered by
1
Let the length of one of the diagonals be 2x and the other be 2y, thencos (76/2) = x/10x = 10 cos 38 = 7.88 cmsin (76/2) = y/10y = 10 sin 38 = 6.16 cm please mark me as brainliest.....
Answered by
0
Step-by-step explanation:
Diagonals of a rhombus intersect et at right angles.
the sides of the rhombus forms the diagnol of each right triangle formed by the intersection of the diagonals.
taking half the angle between the adjacent sides as 38 degrees.
sin 38 = x/ 10
x = 10x sin 38.
the length of the longer diagonal is 2x = 2*10*sin 38
Similar questions