Question

A rhombus has two daigonals 30 cm and 16 cm find its perimeter

Answer 1

Answer:

It is very Easy.....

Step-by-step explanation:

We can say that 8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm...

Since diagonal of a rhombus bisects each other

Now by applying Pythagoras theorem we get,

h² = p² + b²

h² = 8² + 15²

h² = 64 + 225

h² = 289

h = √289

h = 17

Therefore perimeter of the rhombus , 

= 4 * side

= 4 * 17

= 68 cm

Therefore perimeter of the rhombus = 68 cm

I hope that my answer will help u.................................^_^