Question

A rhombus having diagonals of length 10 cm and 16 cm, respectively. Find its area.​

Answer 1

then the diagonals of a rhombus bisect each other perpendicularly.

so

Let’s take Triangle ABO (I am considering AC = 16 cm)

AB = 10 cm is the hypotenuse

AO = 8 cm (half of AC as diagonals bisect)

hence in the triangle ABO , using Pythagorean theorem ,

AO2+BO2=AB2

BO2+82=102

BO2+64=100

BO2=100−64==>36

√(BO2)=√36

BO = 6 cm

therefore diagonal BD=2∗BO

BD = 12 cm

hence area of rhombus = 1/2 * AC * BD

[1/2∗(16∗12)]cm2

96 cm^2

Answer 2

Answer:

mt jao apko meri kasam hai

Step-by-step explanation:

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