Question

a rhombus is 24sq.cm has one of its diagnals of 6cm.find the other diagnal and the side of the rhombus​

Answer 1

Area of rhombus = 1÷2×Diagonal 1× Diagonal 2

=1÷2×6×D2= 24

=24×2÷6

=8

So 8 is the second diagonal.

Now See, there is a formula to find out the side of rhombus, when it's diagonals are given.

Formula=

4 ( A's square )= ( diagonal 1st square) + ( Diagonal 2nd )

A = side of rhombus

= 4(A's square )=(6×6)+(8×8)

=4(A's suare)=36+64

=4(A's square)=100

=A's square= 100÷4

= A's square =25

=A=5

So the length of the side of rhombus is 5 cm
Hope it helps you=)