Question

A Rhombus is two diagonal length 24 mètre and
10 mitre, Perimeter and Area ?​

Answer 1

Step-by-step explanation:

area of rhombus = 1/2 × D1 ×D2

A = 1/2 × 24×10

A = 120 m²

and we know that diagonals of Rhombus bisect each other at right angle.

so perpendicular is half of diagonal 24/2 = 12m

and base of triangle is half of diagonal 10/2 = 5M

IN RIGHT ANGLE TRIANGLE

PYTHAGORAS THEOREM

H² = P² + B²

H = √(12²+5²)

H = √(144+25)

H = √(169)

H = 13m