Math, asked by jabinphilipose1117, 1 year ago

A rhombus of area 24 sq. cm has one of its diagonals of 6 cm. Find the other diagonal and the side of the rhombus

Answers

Answered by Amanthelearner
14
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Answered by aadyaa01
1

Answer: 8cm and 5cm

Step-by-step explanation:

Area of rhombus = 1÷2×Diagonal 1× Diagonal 2

=1÷2×6×D2= 24

=24×2÷6

=8

Area of rhombus = 1÷2×Diagonal 1× Diagonal 2

=1÷2×6×D2= 24

=24×2÷6

=8

So 8 is the second diagonal.

Now See, there is a formula to find out the side of rhombus, when it's diagonals are given.

Formula=

4 ( A's square )= ( diagonal 1st square) + ( Diagonal 2nd )

A = side of rhombus

= 4(A's square )=(6×6)+(8×8)

=4(A's suare)=36+64

=4(A's square)=100

=A's square= 100÷4

= A's square =25

=A=5

So the length of the side of rhombus is 5 cm

Now See, there is a formula to find out the side of rhombus, when it's diagonals are given.

Formula=

4 ( A's square )= ( diagonal 1st square) + ( Diagonal 2nd )

A = side of rhombus

= 4(A's square )=(6×6)+(8×8)

=4(A's suare)=36+64

=4(A's square)=100

=A's square= 100÷4

= A's square =25

=A=5

So the length of the side of rhombus is 5 cm

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