A rhombus of side 30 cm has two diagonal 120 then length of diagonal
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tep-by-step explanation:
rhombus are 60° each. ⇒ other pair of angles are 120° each. Diagonal of a rhombus bisects the angles at the vertices. ∴ Three angles of the triangle formed by the diagonal of a rhombus are 60° each. ⇒ The triangle formed by the rhombus is an equilateral triangle. ⇒ The length of the diagonal of the rhombus = length of the side = 20 cm Diagonals bisect each other. ∴ Length of the half of the diagonal = 20/2 = 10 cm Length of the half of the other diagonal = √[(10)2 + (20)2] = √(100 + 400) = √(500) = √(5 x 100) = 10 √5. Length of the other diagonal of the rhombus = 2 x 10√5 = 20√5 cm
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