Question

A rhombus shaped base has it diagonal 40m and 50m If each tile has dimension 2mx 2m. How many tile are required for tiling of base​

Answer 1

Given,

Measure of one of the diagonals of the rhombus shaped base (p) = 40 m

Measure of the other diagonal of the rhombus shaped base (q) = 50 m

Therefore area of the rhombus shaped base =

$\frac{1}{2} \times p \times q$

$= \frac{1}{2} \times 40 \times 50$

= 1000 m²

Now,

Given dimension of tile = 2 m × 2 m

Therefore, area of one tile = (side)² (since,length=breadth =2m)

= (2 m)²

= 4 m²

Now,

Therefore, number of tiles required for filling the base =

$\frac{area \: of \: base}{area \: of \: one \: tile}$

$= \frac{1000}{4}$

$= 250 \: tiles$

Answer =

Number of tiles required to fill the base = 250

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