Question

A rhombus shaped field has green grass for 15 cows. If each side of the rhombus is 200 m and its one of the

diagonals is 320 m, then find the area of the grass field that will be grazed by each cow.

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Answer 1

Step-by-step explanation:

We have given that :

• Each side of rhombus is 200m
• One of the diognal is 320m

To be find:

• find the area of the grass field that will be grazed by each cow.

Solution :

We will find the area of rhombus shaped field by dividing it into two triangles and using heron's formula of finding area of these. ie

$\sqrt{s(s - a)(s - b)(s - c)}$

whose sides have lengths a, b, and c ,

where

s = semi-perimeter

a = length of side a

b = length of side b

c = length of side c

Semi perimeter of a triangle = (320+200+200)÷2

=360 m

Area »

$\sqrt{360(360 - 320)(360 - 200)(360 - 200)}$

= 19200m^2

so area of whole field = 19200×2=38400m^2

So area will be grazed up by 15 cows =38400/15

= 2560 m^2

Hence each the cow will graze 2560m^2.

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Answer 2

Answer:

We have given that :

Each side of rhombus is 200m

One of the diognal is 320m

To be find:

find the area of the grass field that will be grazed by each cow.

Solution :

We will find the area of rhombus shaped field by dividing it into two triangles and using heron's formula of finding area of these. ie

√[s(s−a)(s−b)(s−c)]

whose sides have lengths a, b, and c ,

where

s = semi-perimeter

s = semi-perimetera = length of side a

s = semi-perimetera = length of side ab = length of side b

s = semi-perimetera = length of side ab = length of side bc = length of side c

Semi perimeter of a triangle = (320+200+200)÷2

=360 m

Area » √{360(360 - 320)(360 - 200)(360 - 200)}

= 19200m^2

so area of whole field = 19200×2=38400m^2

So area will be grazed up by 15 cows =38400/15

= 2560 m^2

Hence each the cow will graze 2560m^2.