Question

a rhombus shaped field has green grass for 18 cows to graze. if each side of the Rhombus is 30 m and it's longer diagonal is 48 metre how much area of grass field will eat cow be getting?

Answer 1

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Area of grass field per cow
=864/18=48m2

Answer 2

Answer:

Each cow will get $48m^2$ area to graze.

Step-by-step explanation

In Triangle POS

In a rhombus all the four sides are equal all the four angles are 90 but the diagonals are not equal. It is different from a square because square has equal diagonals and rhombus doesn't.

As PR=48, PO=24 (As the diagonals are perpendicular to each other they bisect  the diagnol is equally divided)

Using Pythagoras theorem

Pythagoras' theorem states the square of the hypotenuse of a right -angle triangle is the sum of the squares of the other two sides.

${PS^2} = PO^{2} + OS^{2}$

$30^{2} = 24^{2} + OS^{2}$

$900-576=OS^{2} \\\sqrt{324} = OS\\18m =OS$

As OS = 18m QS=36m

Area of rhombus = $\frac{PR*QS}{2}$ = $\frac{48*36}{2} = 864m^2$

So Each cow will get = $\frac{864}{18} = 48m^2$

As the total area of the rhombus is 864$m^2$. This is the area foir 18 cows for each cow the area will be $\frac{864}{18} = 48m^2$. Each cow gets 48$m^2$ to graze on the rhombus-shaped land.