. A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, each cow will be getting ______m2 area of grass field to graze. a) 64 b) 48 c) 864 d) 432 *
Answers
Answer
Option b) 48 m²
Explanation
A rhombus shaped field has green grass for 18 cows to graze.
Total number of cows = 18
Also given that, each side of the rhombus is 30 m and its longer diagonal is 48 m.
Let us assume that ABCD is a rhombus having sides 30 m and of diagonal 48 m.
(as shown in fig.)
In ∆ABD
Semi-perimeter of triangle = (a + b + c)/3
a = 30, b = 30 and c = 48
→ (30 + 30 + 48)/3
→ 108/3
→ 54 m
Area of triangle = √[s(s - a)(s - b)(s - c)]
→ √[54(54 - 30)(54 - 30)(54 - 48)]
→ √[54(24)(24)(6)
→ √[(6*9)(8*3)(8*3)(6)]
→ √[(6*6)(9)(24*24)]
→ 6 × 3 × 24
→ 432 m²
Similarly, Area of ∆BCD = 432 m²
Area of rhoumbus ABCD = Ar.(∆ABD + ∆BCD)
→ (432 + 432) m²
→ 864 m²
Now,
Area of each cow = (Area of rhombus ABCD)/(Total number of cows)
→ 864/18
→ 48 m²
||✪✪ QUESTION ✪✪||
A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, each cow will be getting ______m2 area of grass field to graze. a) 64 b) 48 c) 864 d) 432 *
|| ★★ FORMULA USED ★★ ||
- Diagonals of a Rhombus Bisect each other at 90° in equal parts .
- Pythagoras Theoram .
- Area of Rhombus = 1/2 * Diagonal1 * Diagonal2
|| ✰✰ ANSWER ✰✰ ||
❁❁ Refer To Image First .. ❁❁
From image we can see That ∆DOC is a right angle ∆ right angle at O, and DC is hypotenuse .
Let DO is x m.
Than, using Pythagoras theoram we Get :-
→ X = √(30)² - (24)²
→ x = √(900 - 576)
→ x = √(324)
→ x = 18m. = DO.
So, Diagonal DB = 2*18 = 36m.
So,
→ Area of Rhombus = (1/2) * 36 * 48 = (18 * 48)m²
____________
Now, In Rhombus Shaped Field Their were grass for 18 cows to graze .
So,
→ Each cow graze Area of Field = (Total Area)/18 = (18*48)/18 = 48m². (Option B).