A rhombus sheet whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs.5 per sq. m. Find the cost of painting.
Answers
Answered by
3
perimeter = 4 a = 32 => side = 8m
diagonal c = 10m to find other diagonal d. Then area = c d / 2
cost of painting both sides = 2 * (c d / 2) * 5 Rs
In a Rhombus, c² + d² = 4 a² and c² - d² = 4a² cos Ф
so d² = 4 * 8² - 10² = 156 d = 2 √39 m
Cost = 100 √39 Rs
diagonal c = 10m to find other diagonal d. Then area = c d / 2
cost of painting both sides = 2 * (c d / 2) * 5 Rs
In a Rhombus, c² + d² = 4 a² and c² - d² = 4a² cos Ф
so d² = 4 * 8² - 10² = 156 d = 2 √39 m
Cost = 100 √39 Rs
qwert10:
can you explain without using trignometry
Similar questions