Math, asked by sayalpreepriy1a, 1 year ago

A rhombus sheet, whose perimeter is 32m and one diagonal is 10m long, is painted on both sides at the rate of Rs.5 per m 2 . Find the cost of painting.

Answers

Answered by kvnmurty
7
Side AB = perimeter/ 4 = 32/4 = 8 m.
Diagonal AC = 10m.
Area = AC × BD / 2 m^2
Area of both sides = AC × BD = 10 BD m^2
cost of painting both sides = ₹ 10 BD * 5 = ₹ 50 BD

In a Rhombus, AC² + BD² = 4 AB².
BD² = 4 * 8² - 10² = 156
BD = 2 √39 m

Cost = ₹ 100 √39 = ₹ 624.50
Answered by adith757
2

Answer:

Side of another side of rohmbous=Perimeter/4 =32m/4=8m

One of the diagonal of the rhombus= 10m

Another side of rhombus=8m

In rhombus AC²+BD²=4AB²

BD²=2√39m

Cost=Rs100√39=Rs626

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