Question

a rhombus whose diagonals are 5.2 cm and 6.4 cm longest​

Answer 1

$\huge{\bf{\underline{\underline{\colorbox{lavender}{\color{purple} {αиѕωєя}}}}}}$

Hint – we use the property of Diagonals of rhombus which bisect perpendicular to each other.

We can draw a rhombus whose diagonals are 5.2 cm and 6.4 cm long by following the given procedure.

1. Draw a line segment AC = 5.2 cm.
2. Draw XY, the perpendicular bisector of AC.
3. From XY, cut-off OD = 12(6.4) = 3.2 cm.
4. Similarly, cut-off OB = 12(6.4)= 3.2 cm.
5. Join AD, DCCB and BA.

Thus, ABCD is the required rhombus.

Note - In this type of problem, let any cyclic quadrilateral and apply the property of the circle with its circumferences & some geometric properties and we get a rhombus whose diagonals are 5.2 cm and 6.4 cm long.

Answer 2

$\huge\mathbb\red{ANSWER}$

Draw a line segment AC = 5.2 cm.

Draw a line segment AC = 5.2 cm.Draw XY, the perpendicular bisector of AC.

Draw a line segment AC = 5.2 cm.Draw XY, the perpendicular bisector of AC.From XY, cut-off OD = 12(6.4) = 3.2 cm.

Draw a line segment AC = 5.2 cm.Draw XY, the perpendicular bisector of AC.From XY, cut-off OD = 12(6.4) = 3.2 cm.Similarly, cut-off OB = 12(6.4)= 3.2 cm.

Draw a line segment AC = 5.2 cm.Draw XY, the perpendicular bisector of AC.From XY, cut-off OD = 12(6.4) = 3.2 cm.Similarly, cut-off OB = 12(6.4)= 3.2 cm.Join AD, DCCB and BA.

$\huge\mathbb\blue{☺Thank you ☺}$