A rifle is fired in a valley with parallel vertical walls the echo from one wall is heard in 2.0 sec and the echo from the other wall is heard 2sec later what is the width of the valley?
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Hey Dear,
● Answer -
W = 1020 m
● Explaination -
# Given -
t1 = 2 s
t2 = 2+2 = 4 s
# Solution -
Distance of the 1st wall from shooter -
s1 = vt1 / 2
s1 = 340 × 2 / 2
s1 = 340 m
Distance of the 2nd wall from shooter -
s2 = vt2 / 2
s2 = 340 × 4 / 2
s2 = 680 m
Total width of the valley is -
W = s1 + s2
W = 340 + 680
W = 1020 m
Hence, total width of the valley is 1020 m.
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