a rifle of 2kg fires a bullet of mass 0.02kg. the bullet leaves the barrel of the rifle at a velocity of 100m/s . if the bullet takes 0.002s to move through its barrel , calculate the force experienced by the rifle due to its recoil.
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v=u+at
100=0+0.oo2a
a=50,000
f=ma
f =0.02 x 50,000
f= 1,000 N
100=0+0.oo2a
a=50,000
f=ma
f =0.02 x 50,000
f= 1,000 N
Answered by
0
Explanation:
v=u + at
100 = 0+0. 002 a
a=50,000
f = ma
f = ma
f = 0.02×50,000
f = 1,000 N
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