Question

a right angle triangle has a largest sides as 13 cm and one of the sides containing the right angles as 12 cm and its area in centimetre2 is ??
a 30 b 39
c 80 d 78
guys solve this question with reason..

Answer 1

Consider ΔABC in which ∠B = 90°

So AC is the longest side (Hypotenuse) ∴ AC = 13 cm as given in the question

Also Sides Containing right angle are AB and BC, Consider AB = 12 cm

Using Pythagoras Theorem

AC² = AB² + BC²

13² = 12² + BC²

BC² = 169 - 144

BC = √25

BC = 5 cm

We know area of triangle is 1/2 × Base × Height

∴ Area (ABC) = 1/2 × 12 × 5

= 30 cm²

Hence, Option A is the correct answer.

Answer 2

THE ANSWER IS OPTION A) 30
REASON :
LARGEST SIDE=13(HYPO)
ONE SIDE =12(BASE)
ANOTHER SIDE=? (HEIGHT)
HYPO SQUARE =OPPO SQUARE +ADJ SQUARE
13 SQUARE =12 SQUARE +ADJ SQUARE
ADJ SQUARE =169-144
ADJ(HEIGHT) =5
AREA OF TRIANGLE =1/2*BASE *HEIGHT
=1/2*12*5
=6*5
AREA OF TRIANGLE =30