Question

A right angle triangle have angleAOB=90°, AC=BC, OA=10cm and OC=13cm and OB is its base. Find the area of ∆AOB

Answer 1

Answer:

107.9 CM ^2

Step-by-step explanation:

OC^2=OA^+OB^2

OC^2-OA^2 =OB^2

13^2-10^2=OB^2

169-100=OB^2

69=OB^2

8.3=OB

OB×OA =area

8.3×13=area

107.9=area

Answer 2

Answer: your answer is 5 root - 69

Step-by-step explanation:

You'll get the answer from the image I'm sending...

Hope it helps you...

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