Question

a right angle triangle have base 4cm and altitude 8cm . What is the length of hypothenuse
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Answer 1

Answer: h²= a²+b²

h²=4²+8²

h²=16+64

h²=80

h=√80

Step-by-step explanation:

Answer 2

Answer:

330 sqcm

Step-by-step explanation:

a+b+c=132cm

Hypotenuse be c=61cm

a+b=132–61=71cm

√a^2+b^2=61

a^2+b^2=66^2=3721  

(a+b)^2=71^2=5041

(a^2+b^2)+2ab=5041sub stituting the value o f (a^2+b^2) we get

3721+2ab=5041

2ab=1320

ab=660. a=660/b

a^2+b^2=61^2 a+b=71given  

(660/b)+b=71

660+b^2=71b

b^2–71b+660=0

(b-11)(b-60)=0

b=11or 60

a=660/11=60

Side a=60cm

Side b=11cm

Area =1/2ab =1/2*60′11

=330 sqcm