Math, asked by Bhanuprakash5, 11 months ago

A right angle triangle the two perpendicular sides are in ratio of 8:15 the perimeter of the triangle is 80 cm find the sides of the triangle

Answers

Answered by RvChaudharY50

Question :------ we have to Find sides of Right angle ∆ ...

Given :-------

perpendicular sides are in ratio 8:15
perimeter of ∆ = 80cm

Solution :-----------

Formula used :-

Pythagoras Theoram
perimeter of ∆ = sum of sides
Triplet Ratio

we can solve this by 2 methods ..

My First approach will be basic method first ..

Soltution (1) :--------

Let perpendicular sides of ∆ be 8x and 15x .

Than its Hypotenuse by pythagoras Theoram will be :--

(8x)² + (15x)² = H²

64x² + 225x² = H²

H² = 289x²

H = √(289x²) = 17x

Now, it is given that its perimeter is 80cm.

so,

8x+15x+17x = 80

40x = 80

x = 2

so, our sides of ∆ will be :--- 8x = 8×2 = 16cm

15x = 15×2 = 30cm

17x = 17×2 = 34 cm ... (Ans)

______________________________

Solution (2)

If we know Triplet ratio we can easily find it without x ..

we know that,

8:15:17 are triplet ratios ...

so,