Question

a right angle triangle with vertices P,Q,R .PQ=3cm QR=4cm angle Q =90 Angle R =theta (trigonometry) so find the trigonomatric ratio of R theta ? ​

Answer 1

Step-by-step explanation:

sin theta = PQ/PR. 3/5

cos theta = QR/PR. 4/5

tan theta = PQ/QR. 3/4

cosec theta = PR/PQ. 5/3

sec theta = PR/QR. 5/4

cot theta = QR/PQ. 4/3