A right angle triangleABC with sides 3 cm 4 cm 5 cm is revolved about the fixed side of 4 cm. Find the volume of the solid generated and also fine total surface area
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Answered by
0
volume of cone = 1/3 π r3
r = 3
then for the TSA...
TSA of cone= πrl
r=3
l= 5
r = 3
then for the TSA...
TSA of cone= πrl
r=3
l= 5
Answered by
3
as rt. is revolved around 4cm =>while revolving a cone is formed whose
h=4cm ,r=3cm,l=5cm
volume of cone =1/3*22/7*r2h
=1/3*22/7*3*3*4
=22/7*3*4
=22/7*12
=264/7cm³ or 37.71cm³(approximately)
total surface area =22/7×l +22/7r²
=22/7(l+r²) - - - -(taking 22/7 common)
=22/7×(5+9)
=22/7×13
=286/7cm² or 40.85cm²(approximately)
h=4cm ,r=3cm,l=5cm
volume of cone =1/3*22/7*r2h
=1/3*22/7*3*3*4
=22/7*3*4
=22/7*12
=264/7cm³ or 37.71cm³(approximately)
total surface area =22/7×l +22/7r²
=22/7(l+r²) - - - -(taking 22/7 common)
=22/7×(5+9)
=22/7×13
=286/7cm² or 40.85cm²(approximately)
1092837465:
Thanks man for solving this
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