CBSE BOARD X, asked by menkakadam9, 5 months ago

A right-angled AABC with sides 3 cm, 4 cm and 5 cm is revolved about the fixed side of 4 cm. Find the volume of the solid generated. Also, find the total surface area of the solid.​

Answers

Answered by nadeemzaalima
7

Answer:

see below my answer... may it will help you a bit

Explanation:

When rt. ∠ed △ABC is revolved about AB = 4 cm, it forms a right circular cone of radius 3 cm and height 4 cm . Slant height of the cone is 5 cm.

Volume of cone = 1 / 3 πr2h

1 / 3 × 22 / 7 × 3 × 3 × 4

= 37.71 cm3

Total surface area of the solid = πr2 + πrl = πr (r + l )

= 22 / 7 × 3 × 8 = 75.43 cm2

Answered by wangliburagohain
2

Answer:75.43 cm2

Explanation:Volume of cone = 1 / 3 πr2h  

1 / 3 × 22 / 7 × 3 × 3 × 4

= 37.71 cm3  

Total surface area of the solid = πr2 + πrl = πr (r + l )  

= 22 / 7  × 3 × 8 = 75.43 cm2

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