a right-angled is to be constructed so that the hypothenuse is 20 cm long. the height of the triangle is 4 cm longer than the base of the triangle. evaluate the length of each side of the triangle
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let the base be x
then the height is x+4
by Pythagoras theorem
20^2=x^2+(x+4)^2
400=x^2+x^2+16+8x
400=2x^2+16+8x
400=2(x^2+8+4x)
400/2=x^2+4x+8
200-8=x^2+4x
x^2+4x-196=0
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