Question

A right angled isosceles triangle ABC is right angled at A . Then find angle b .
simplify and factorize : ( a + b + c) square - ( a - b - c ) square +4b square -4csquare

Answer 1

here in the question it is given that  a²=b²+c²                                                      but the given angle is  right angle  so, angle B =90-angle C   then...........
(a+b+c)-(a-b-c)+4b²-4c²
that ia equal to
=a²+b²+c²+2ab +2bc+2ac-a²-b²-c²+2ab-2bc+4b²-4c²
=4ab+4ac+4b²-4c²
take 4a common then we get;
4a(b+c)+4(b+c)(b-c)
in 4a and4 take four common at last we get;
4(a+b-c)(b+c)
this is the answer and HOPE IT HELPS U 
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