Question

A right angled isosceles triangle is inscribed
in the circle x2+y2-4x-2y-4=0 then length of
the side of the triangle is​

Answer 1

Answer:

3root2

The given circle is,  

x2  +y2  -4x-2y-4 = 0  

Now comparing this equation of circle with standard equation of circle,  

x2 +y2  +2gx + 2fy +c = 0 ​we get,

g = -2 , f = -1 c = -4 so the center of the circle will be (-g, -f) or (2, 1) and radius can be calculated as