a right angled isosocel triangle ABC is the right angled at A, find the value of angle B
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Answer:
45°
Step-by-step explanation:
In triangle ABC, AB = AC. [since any other pair can't be equal]
Therefore, angle B = angle C [ angles opposite to equal sides in a triangle, are equal]
It is given that angle A = 90°
Now, angle A + angle B + angle C = 180° [angle sum property of a triangle]
=> 90° + angle B + angle B = 180° [ since angle B = C]
=> 2 angleB = 180° - 90°
=> angle B = 90°/2
=> angle B = 45° = angle C
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