Question

a right angled triangle abc is right angled at b and tan=4/3 if ac=25cm the length of bc is

Answer 1

height = AB, base=BC, hypotenuse=AC

sec^2A=tan^2A+1. {Formula}

sec^2A=16/9+1

sec^2A=25/9

sec A=5/3

sec A=1/cos A. {Formula}

cos A=3/5

cos A= base/hypotenuse=BC/AC

3/5=BC/25

BC=15 cm

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