Question

a right angled triangle abc is right angled at b. bd is perpendicular to ac. prove:(1)∆adb~∆bdc​

Answer 1

Step-by-step explanation:

In triangle ABC is right - angled at B and BD is perpendicular to AC , then find: cot DBA is m/12 . value of m is,

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In ABC AB^2 + BC^2 = AC^2 (By Pythagoras theorem) 12^2 + 5^2 = AC^2 AC^2 = 169 AC = 13 In ABC A + B + C = 180 A + C = 90 (As B = 90 ).....(i)In ABD , A ... More