Question

a right angled triangle abc is right angled at b. bd is perpendicular to ac. prove:(1)∆adb~∆bdc(2)∆adb~abc(3)∆abc~∆bdc(4)bd^2=ad×dc(5)ab^2=ad×ac(6)bc^2=cd×ac ​

Answer 1

Answer:

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Answer 2

Answer:

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