a right angled triangle has an area of 8 cm square find its hypotenuse
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The hypotenuse cannot be found for right triangle. So , considering it as an isosceles triangle .
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Both the perpendicular and base are equal in length.
So Area of triangle = 1/2 x b x h
Let b = h = y
1/2 x y x y = 8
y² = 16
y = 4
So Perpendicular = Base = 4 cm
Now by Pythagoras theorem,
4² + 4² = √ 16+ 16 = √32 = 4√2 cm
So required hypotenuse = 4√2 cm
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