A right angled triangle has its area numerically equal to its perimeter the length of each side is an even number and the hypotenuse is 10cm what is the perimeter of the triangle. (3)
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hyp.=10
base=?
height=?
peri.=10+s+b
area=s×b÷2
10+s+b=s×b÷2
20+2s+2b=s×b
and by Pyth. theorem
10^2=b^2+s^2
I hope u can solve further cause I'm not having paper and pen at the moment....
sry....
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