Question

A right angled triangle of which the sides containing the right angle are 6.3 cm and 10 cm in length, is made to turn round on the longer side. Find the volume of the solid, thus generated. Also, find its curved surface.

Answer 1

The volume of the solid is $\mathbf{415.8 \ cm^{3}}$

Step-by-step explanation:

• Here right angle triangle is rotated about its longer side. Solid is form known as cone.

• So

        Height of cone (H) = 10 cm

        Radius of cone (R) = 6.3 cm

• We know the volume of cone$\mathbf{=\frac{1}{3}\pi R^{2}H}$

        On putting respective value in above equation, we get

        $\mathbf{\textrm{Volume of cone}=\frac{1}{3}\times \frac{22}{7}\times 6.3^{2}\times 10}$

         On solving

        Volume of cone $\mathbf{=415.8 \ cm^{3}=}$ This is volume of solid

Answer 2

Answer:

Hello There,

This is your answer.

Step-by-step explanation:

We know that the volume of a right circular cone with radius r and height h is V= 1 / 3 * πr^2 * h.

It is given that the height of the solid is h = 10 cm and radius is 6.3 cm, therefore,

V= 1 / 3 * πr^2 * h

= 1 / 3 × 22 / 7 × (6.3)^2 × 10

= 1 / 3 × 22 / 7 × 39.69 × 10 = 415.8 cm^3

Hence, the volume of the solid is 415.8 cm^3

HOPE THIS ANSWER HELPS YOU!!!

HAVE A GREAT DAY AHEAD!!!

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