Question

a right angled triangle.
Q.8. Triangle ABC and triangle PQR are two
similar triangles. The area of these are 64 cm² and
100 cm² respectively. If QR = 12 cm. If QR = 12 .​

Answer 1

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Triangle ABC similar to triangle pqr area of triangle ABC and pqr 64 CM square and hundred CM square respectively if BC is equal to 4 cm then find QR

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ΔABC ≈ Δ PQR

Area of Δ PQR / Area of ΔABC = (PQ/AB)² = (QR/BC)² = (PR/AC)²

Area of Δ PQR = 100 cm²

Area of Δ ABC = 64 cm²

BC = 4 cm

QR = ?

Area of Δ PQR / Area of ΔABC = (QR/BC)²

=> 100 /64 = (QR/4)²

=> 25 / 16 = QR²/16

=> QR² = 25

=> QR = 5 cm

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