A right circular cone having radius 5 cm and height 12 cm is given. The curved surface area of the cone is ki
Answers
Explanation:
As we know the, the total surface area of cuboid (TSA)=
\sf{ = 2(length \times breadth + breadth \times height + heigh \times length}=2(length×breadth+breadth×height+heigh×length
Now, putting the values, we get,
\sf{\implies \: TSA = 2(20 \times 15 + 15 \times 18 + 18 \times 20}⟹TSA=2(20×15+15×18+18×20
\sf{\implies TSA = 2(300 + 270 + 360}⟹TSA=2(300+270+360
\sf{\implies TSA = 2 \times 930}⟹TSA=2×930
\sf{\implies TSA = 1860}⟹TSA=1860
Now,
The lateral surface area of the cuboid (LSA)=
\sf{\implies 2 \times height( length+breadth)}⟹2×height(length+breadth)
Now, putting the values, we get,
\sf{\implies LSA = \: 2 \times 18(20 + 15)}⟹LSA=2×18(20+15)
\sf{\implies LSA = 2 \times 18 \times 35 }⟹LSA=2×18×35
\sf{\implies LSA = 1260}⟹LSA=1260
Hence, the total surface area and the lateral surface area of the cuboid are 1860cm² and 1260cm².
The slant height would be the hypoteneuse of a right triangle whoses are the base radius and height. Pythagorus taught us the rest.
Slant height. = √(5² + 7²). = √(25 + 49)
= √74. Or approx 8.6 cm.
Surface Area = area of base + area of sl0ped arwa.
Aeea of base = πr² = 25π
Area of sloped side: = 1/2 circ of base × slant height
= 1/2 × 2π 5 × √74 =™5√(74)π
Total surface area = (25+5√74)π
.=( 25+5×8.6)π = (25+43)π = 68π or approx 213.63 cm²