A right circular cone is 3.6cm high and radius of its base is 1.6 cm. It is melted and recast into right circular cone with radius of its base as 1.2cm.Find its height
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For cone, h = 3.6 cm, r = 1.6 cm
Volume of the given cone = 1/3 x Π 2 h = (1/3 x 22/7 x 1.6 x .16 x 3.6) cm2
Radius of the second cone = 1.2 cm. Let its height be h1</sup> then,
Volume of the second cone = 1/3 x Π r2 h = 1/3 x 22/7 x 1.2 x h1
it is melted and recasted so , the volume of the cones would be equal, therefore
1/3 x 22/7 x 1.2 x h1 = 1/3 x 22/7 x 1.6 x .16 x 3.6
h1 = (1.6 x 1.6 x 1.6) / (1.2 x 1.2) = 6.4
Hence the height of the second cone is 6.4 cm
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