a right circular cone is of height 8.4 cm and radius of its base is 2.1 cm It is melted and recast into spare find the radius of the sphere
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Answered by
16
we know that: the right circular cone is melted and recast into a sphere, then the volume of cone will be exactly equal to the volume of sphere.
Vc= Vs;
πR²h/3= 4πr³/3;π×2.1²×8.4/3=4πr³/3;
38.808 = 4πr³/3;
3×38.808=4πr³/3;
4πr³=116.424;
r³=116.424/4π;
r³ = 9.261;
r = ∛9.261;
r = 2.1 cm
So, the radius of the sphere is 2.1 cm
bye :-)
Answered by
26
EXPLANATION.
Right circular cone of height = 8.4 cm.
Radius of its base = 2.1 cm.
It is melted and recast into sphere.
As we know that,
Volume of a cone = 1/3πr²h.
Volume of sphere = 4/3πr³.
Using this formula in the equation, we get.
Volume of cone = Volume of sphere.
⇒ 1/3πR²h = 4/3πr³.
⇒ πR²h = 4πr³.
⇒ R²h = 4r³.
⇒ (2.1)² x 8.4 = 4 x r³.
⇒ 4.41 x 8.4 = 4 x r³.
⇒ 37.044 = 4 x r³.
⇒ r³ = 9.261.
⇒ r³ = (2.1)³.
⇒ r = 2.1 cm.
Radius of sphere = 2.1 cm.
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