A right circular cone made of iron is of 8 cm height and has base radius 2 cm It is melted and recast into a sphere determine the radius of the sphere
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given radius of cone = 2 cm
height of cone = 8cm
let the radius of sphere be R cm so,
vol. of cone = vol. of sphere
1/3 πr²h = 4/3 π R³
r²h=4R³
R³= r²h/4
R³= (2)²8/4
R³=8
R=∛8
R= 2 cm
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height of cone = 8cm
let the radius of sphere be R cm so,
vol. of cone = vol. of sphere
1/3 πr²h = 4/3 π R³
r²h=4R³
R³= r²h/4
R³= (2)²8/4
R³=8
R=∛8
R= 2 cm
i hope u like it so plzzz mark as brainliest plzzzz.....
Answered by
8
Here,
Volume of the cone = volume of the sphere.
1/3πr²h = 4/3πr³
1/3 × 22/7 × (2)² × 8 = 4/3 × 22/7 × r³
1/3 × 4 × 8 = 4/3 × r³
32/3 × 3/4 = r³
8 = r³
r = ³√8
r = 2 .
Therefore, radius of the sphere = 2 cm.
:)
Volume of the cone = volume of the sphere.
1/3πr²h = 4/3πr³
1/3 × 22/7 × (2)² × 8 = 4/3 × 22/7 × r³
1/3 × 4 × 8 = 4/3 × r³
32/3 × 3/4 = r³
8 = r³
r = ³√8
r = 2 .
Therefore, radius of the sphere = 2 cm.
:)
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