A right circular cone of diameter "r" cm and height 12 cm rests on base of a right cylinder of radius "r"cm.Their bases are in the same plane and the cylinder is filled with water up to a height of 12 cm.If the cone is to be removed,find the height to which water level will fall?
Answers
Diameter of base of cone = r cm
Radius of base of cone = r/2 cm
Radius of base of cylinder = r cm
Height of cone =12cm
Height of water in cylinder before cone was taken out = 12cm
∴Volume of water left in cylinder when cone is removed out = Volume of water - Volume of cone
= πr2h = (1/3)πr2h
= 12πr2 – (1/3)π(r/2)2(12)
= 12πr2 - πr2
= 11πr2
Thus, height to which the water level will fall = 11 cm, which is the present height of water left in cylinder.
Answer:
Diameter of base of cone = r cm
Radius of base of cone = r/2 cm
Radius of base of cylinder = r cm
Height of cone =12cm
Height of water in cylinder before cone was taken out = 12cm
∴Volume of water left in cylinder when cone is removed out = Volume of water - Volume of cone
= πr2h = (1/3)πr2h
= 12πr2 – (1/3)π(r/2)2(12)
= 12πr2 - πr2
= 11πr2
Thus, height to which the water level will fall = 11 cm, which is the present height of water left in cylinder.