A right circular cone with radius equal to 5 cm and height 12 cm is given. The total surface
area of the cone is
Answers
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Given :- A right circular cone with radius equal to 5 cm and height 12 cm is given. The total surface area of the cone is ?
Solution :-
we know that,
- slant height of cone is = √[(radius)² + (height)²]
- CSA of cone = π * radius * slant height.
- Area of Base = π * (radius)²
- TSA of cone = CSA + Area of Base.
given that,
- radius = 5cm.
- Height = 12cm.
So,
→ slant height of cone = √[5² + 12²] = √(25 + 144) = √(169) = 13 cm.
Than,
→ CSA of cone = π * radius * slant height .
→ CSA = 3.14 * 5 * 13
→ CSA = 3.14 * 65
→ CSA = 204.1 cm².
and,
→ Area of Base = π * (radius)²
→ Area of Base = 3.14 * (5)²
→ Area of Base = 3.14 * 25
→ Area of Base = 78.5 m².
Therefore,
→ TSA of cone = CSA + Area of Base .
→ TSA of cone = 204.1 + 78.5
→ TSA of cone = 282.6 m².
Hence, Total surface area of cone is 282.6 m².
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