a right circular cylinder and a right circular cone have equal bases and equal heights.if their curved surfaces are in the ratio 8:5,show that the ratio of the radius of the base to the height is 3:4 for each of them
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Hey here is your answer
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Let height be 'h' and radius be 'r' and length be 'l'
Area of circular cone = πrl
area of cylinder = 2πrh
A/Q
2πrh/πrl = 8/5
5h = 4l
5h = 4√r² + h²
since ..l = √h² + r²
25h² = 16( r² + h²)
25h² - 16h² = 16r²
9h² = 16r²
r²/h² = 9/16
r²/h² = 3:4
Since the ratio is 3:4..
=====================
I Hope it will help you
Thank you
☺️
=====================
Let height be 'h' and radius be 'r' and length be 'l'
Area of circular cone = πrl
area of cylinder = 2πrh
A/Q
2πrh/πrl = 8/5
5h = 4l
5h = 4√r² + h²
since ..l = √h² + r²
25h² = 16( r² + h²)
25h² - 16h² = 16r²
9h² = 16r²
r²/h² = 9/16
r²/h² = 3:4
Since the ratio is 3:4..
=====================
I Hope it will help you
Thank you
☺️
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