Math, asked by Yuvrajsingh2834, 1 year ago

a right circular cylinder has a curved surface area there are 1320 cm square and the radius of its base is 10.5 cm find the height and volume of the cylinder of class 8 given CSA 1320 CM SQUARE RADIUS OF ITS BASE 10.5

Answers

Answered by divyanshbhati192004
1

Answer: curved surface area of closed cylinder=1320 centimetre square

Radius=10.5

CSA of closed cylindrical is equal to=1320

Step-by-step explanation:


divyanshbhati192004: CSA of closed cylindrical is equal to=1320
divyanshbhati192004: 2 π r h=1320
divyanshbhati192004: h=1320*7/22*10.5
divyanshbhati192004: HENCE,HIGHT OF closed cylindrical is equal to 4,284 .
Answered by wifilethbridge
5

The height of cylinder is 20 cm and the volume of cylinder is 6930 cubic cm

Step-by-step explanation:

Curved surface area of cylinder =2 \pi rh

Radius of cylinder = 10.5 cm

So, Curved surface area of cylinder= 2 \times \frac{22}{7} \times (10.5) \times h

We are given that a right circular cylinder has a curved surface area there are 1320 cm square

So,  2 \times \frac{22}{7} \times (10.5) \times h =1320

h = \frac{1320 \times 7}{2 \times 22 \times 10.5}

h = 20 cm

Volume of cylinder = \pi r^2 h = \frac{22}{7} \times 10.5^2 (20)=6930 cm^3

Hence the height of cylinder is 20 cm and the volume of cylinder is 6930 cubic cm

#Learn more;

A right circular cylinder has base radius 10.5 cm and height 14 cm. find its CSA

https://brainly.in/question/7343574

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