Math, asked by saminulali123456, 5 months ago

A right circular cylinder has the circular base of diameter 28 cm and height of llcm. Find:
(a) lateral surface area
(b) total surface area
(c) volume

Also write how
π = 22/7

Answers

Answered by smrutiswain24
3

Step-by-step explanation:

GIVEN :- height = 11cm

diameter =28cm

radius = 28/2 = 14 cm

Now lateral surface area of cylinder is

2\pi \: rh

= 2 × 22/7 × 28/2 ×11

2×11×4×11 (2 will calcen 22 where we will get 11 . And 7 will cancle 28 where we will get 4)

968cm²

Now , total surface area of cylinder

2\pi \: r(r + h)

= 2×22/7×28/2 (14 + 11)

= 2 × 22/7 ×28/2 ×25 (14 + 11 = 25)

=

= 2×11×4×25 (2 will calcen 22 where we will get 11 . And 7 will cancle 28 where we will get 4)

= 2200cm²

Now volume of cylinder

\pi \: r {}^{2} h

= 22/7 × 28 /2 × 28/2 × 11

=11 × 4 × 28/2 ×11

= 11 × 4 × 28/2 ×11 ( 2 will calcel 22 where we will get 11 and 7 will calcen 28 where we will get 4 )

11× 2×28×11 ( 2 will calcen 4 we will get 2)

6776cm³

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Answered by Anonymous
2

Answer:

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