A right circular cylinder is closed at both ends . Find the cost of polishing its total surface at 25 paise per square am if the radius of the cylinder is 7 cm and depth is 12 cm .
Answers
Answered by
47
Hola!!
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ANSWER:
Given:
r = 7 cm
h = 12 cm
Rate = 25 paise/cm^2
To find:
Cost
Solution:
TSA = 2πr(r+h)
= 2 × 22/7 × 7 ( 7 + 12 )
= 44 × 19
= 836 cm^2
Now that we have surface area we can find cost using following formula
Cost = Rate × SA
= 25 × 836
= 20900 paise
1 Rs = 100 paise
therefore 20900/100
Therefore Cost of polishing is Rs 209
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Hope this helps!
==================================
ANSWER:
Given:
r = 7 cm
h = 12 cm
Rate = 25 paise/cm^2
To find:
Cost
Solution:
TSA = 2πr(r+h)
= 2 × 22/7 × 7 ( 7 + 12 )
= 44 × 19
= 836 cm^2
Now that we have surface area we can find cost using following formula
Cost = Rate × SA
= 25 × 836
= 20900 paise
1 Rs = 100 paise
therefore 20900/100
Therefore Cost of polishing is Rs 209
=================================
Hope this helps!
Answered by
17
Answer:5222.897/- rs. If it 25 paise per sq.cm
Step-by-step explanation:surface area of cylinder is
2*pie*r(r+h)..cm^2
Given 25 paise per sq.cm
Total money required is
surface area*cost per sq.cm
So total cost= 835.67*25=130572.44 paise=5222.897 rs...
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