A right circular cylinder is partially filled with water. Two iron spherical balls are completely immersed in the water so that the height of the water in the cylinder rises by 4 cm. If the radius of one ball is half of the other and the diameter of the cylinder is 18 cm, then the radii of the spherical balls are
A) 6 cm and 12 cm B) 4 cm and 8 cm C) 3 cm and 6 cm D) 2 cm and 4 cm
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Answer:
(C) 3 cm and 6 cm
Step-by-step explanation:
total volume of 2 balls = volume of cylinder of height = 4 cm
43πr31+43πr32=π92×4
r1=2r2 given
43π(8r32+r32)=π×9×9×4
9r32=9×9×3
r2=3
r1=2r2=2×3=6
may it help u ♥️
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