Question

A right circular cylinder just encloses a sphere of radius ( r ) . Find -:

a ) Surface area of the sphere

b) Curved surface area of the cylinder,

c) Ratio of the areas obtained in ( a ) and ( b ).

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Answer 1

$\small \bold{(i) SA \: of \: sphere =4πr^2}$

(ii) Height =r+r=2r

radius =r

$\small \bold{⇒Curved \: Surface \: Area=2πrh=2πr(2r)=4πr^2}$

$(iii) Ratio = \frac{4\pi {r}^{2} }{4\pi {r}^{2} } = \frac{1}{1} \: or \: 1 :1$

Answer 2

Answer:

curved surface area of cylinder i 2πrh where r is the radius of the base of the cylinder and it is the height of the cylinder the right circular cylinder and closed a sphere of radius r curved surface area of a cylinder of train is 4 πr2

Step-by-step explanation:

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