Question

A right circular cylinder of height 10 cm and circular base of radius 5cm is filled to half of radius of its capacity by water. The cylinder is tilted so that no water goes out of the cylinder. The angle from the vertical by which the cylinder is tilted? ​

Answer 1

Answer:

TSA of remaining solid = TSA of cylinder - TSA of cone

= 2πr(r+h) - πr(r+l)

= πr(2r + 2h - r + l)

=22 / 7 × 6 ( 20+6+11.66)

=22 / 7 × 6 × 37.66

=710.16cm^2

volume of remaining solid = Volume of Cylinder - volume of cone

=πr^2h - 1/3πr^2h

=2 /3πr^2h

=2 /3×22 /7×6×6×10

=753.6cm^3