Question

A right circular cylinder with base radius 14 cm, height 35 cm​,
Find the volume, CSA, TSA of right circular cylinder.
​
Bye... ​

Answer 1

Answer:

Here's your answer

Step-by-step explanation:

For A Right Circular Cylinder :

Given =>

•    Base Radius , r = 14 cm
•    Height , h = 35 cm

To find =>

• CSA of cylinder
• TSA of cylinder
• Volume of cylinder

Formulas for each =>

• CSA of cylinder = 2πrh
• TSA of cylinder = 2πr(r + h)
• Volume of cylinder = πr²h

Where ,

   r = Base Radius of Cylinder

   h = height of Cylinder

   π = 22/7

We Have ,

   r = 14 cm

   h = 35 cm

✏ Calculating CSA of Cylinder :

Using Formula of CSA

CSA = 2πrh

= 2 * 22/7 * 14 * 35

= 44 * 70

CSA = 3080cm²

✏ Calculating TSA of Cylinder :

Using Formula of TSA

TSA = 2πr(r + h)

= 2 * 22/7 * 14 (14 + 35)

2 * 227 * 14 * 49

TSA = 4312cm²

✏Calculating Volume of Cylinder :

Using Formula of Volume

Vol = πr²h

= 22/7 * 14 * 14 * 14 * 35

Vol = 21560cm³

Hence

• CSA of cylinder = 3080cm²
• TSA of cylinder = 4312cm²
• Volume of cylinder = 21560cm³

Hope you understand.

Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

Find the volume , CSA ( Curved Surface Area ) , TSA ( Total Surface Area ) of right circular cylinder with base radius 14 cm , height 35 cm.

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

• Volume of cylinder = $\sf21560\:{cm}^{3}$

• CSA of cylinder = $\sf3080\:{cm}^{2}$

• TSA of cylinder = $\sf4312\:{cm}^{2}$

$\huge\purple{ \underline{ \boxed{\mathbb{\red{EXPLANATION : }}}}}$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

• Radius of right circular cylinder ( r )= 14 cm

• Height of right circular cylinder ( h )= 35 cm

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

• Volume of right circular cylinder

• CSA of right circular cylinder

• TSA of right circular cylinder

$\green{ \large \underline{ \mathbb{\underline{FORMULAS \: USED: }}}}$

$\purple{ \boxed{ \begin{array}{l} \textsf{Volume of cylinder = \sf\pi {r}^{2}h } \\ \\ \textsf{CSA of cylinder = \sf2\pi rh } \\ \\ \textsf{TSA of cylinder = \sf2\pi r(h + r) } \end{array}}}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\red{ \underline{\underline{\textsf{Volume of cylinder : }}}}$

$\displaystyle \longrightarrow \textsf{Volume of cylinder } \sf = \frac{22}{ \cancel7} \times {(14)}^{2} \times \cancel{35} { \: \: }^{5} \: \\ \\ \displaystyle \longrightarrow \textsf{Volume of cylinder } \sf =22 \times 196 \times 5 \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \longrightarrow \textsf{Volume of cylinder } \sf =21560 \: {cm}^{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\red{ \underline{\underline{\textsf{CSA of cylinder : }}}}$

$\displaystyle \longrightarrow \textsf{CSA of cylinder } \sf = 2 \times \frac{22}{ \cancel7} \times 14 \times \cancel{35} { \: \: }^{5} \: \: \: \: \\ \\ \displaystyle \longrightarrow \textsf{CSA of cylinder } \sf = 2 \times 22 \times 14 \times 5\: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \longrightarrow \textsf{CSA of cylinder } \sf =3080 \: {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\red{ \underline{\underline{\textsf{TSA of cylinder : }}}}$

$\displaystyle \longrightarrow \textsf{TSA of cylinder } \sf = 2 \times \frac{22}{ \cancel7} \times \cancel{14} { \: \: }^{2} \: (35 + 14) \: \: \: \: \\ \\ \displaystyle \longrightarrow \textsf{TSA of cylinder } \sf = 2 \times 22 \times 2 \times 49\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \longrightarrow \textsf{TSA of cylinder } \sf =4312 \: {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\purple{ \boxed{ \begin{array}{l} \textsf{Volume of cylinder = \sf21560 \: {cm}^{3} } \\ \\ \textsf{CSA of cylinder = \sf3080 \: {cm}^{2} } \\ \\ \textsf{TSA of cylinder = \sf4312 \: {cm}^{2} } \end{array}}}$