Question

A right pyramid with a square base has a base edge length of 24 feet and slant height of 20 feet. The height of the pyramid is 'blank' feet.

Answer 1

The height of the pyramid is 16 feet.

Explanation

According to the below diagram, $AB$ is a base edge of the square base which is given as 24 ft.

So, $AD=BD= \frac{1}{2}AB = 12 ft$

The slant height of the pyramid is $BC$, which is 20 ft.

Suppose, the height of the pyramid $(CD) = h$ ft.

So, in right triangle $BDC$, using Pythagorean theorem.....

$CD^2+BD^2= BC^2\\ \\ h^2+(12)^2=(20)^2\\ \\ h^2+144=400\\ \\ h^2= 400-144=256\\ \\ h=\sqrt{256}=16$

So, the height of the pyramid is 16 ft.

Answer 2

Answer:

So, the height of the pyramid is 16 ft.