Math, asked by Pinkthingz48, 4 months ago

A right rectangular prism has these dimensions:

Length − Fraction 1 and 1 over 3 units
Width − Fraction 5 over 6 unit
Height − Fraction 2 over 3 unit

How many cubes of side length 1 over 6 unit are required to completely pack the prism without any gap or overlap?

Answers

Answered by darksoul3
12

\large\bf{\underline\orange{Answer \:↝}}

Volume Prism = (1 + 1/2) (1/2) (3/4) = (3/2) (1/2) (3/4) = (9/16) units³

Volume of one cube = (1/4)³ = 1/64 units³

So,

(9/16) / (1/64)

(9/16) × (64/1)

(64/16) (9/1)

4 × 9 = 36

Answered by DangerousBomb
16

\huge\bf{\underline\red{Answer \: ⇝}}

Volume Prism = (1 + 1/2) (1/2) (3/4) = (3/2)

(1/2) (3/4) = (9/16) units³

Volume of one cube = (1/4)³ = 1/64 units³

So,

(9/16) / (1/64)

(9/16) × (64/1)

(64/16) (9/1)

4 × 9 = 36


harisingh03061986: hi
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